Mixture and Allegation 🌹

3*8:2*9 = 4:3 = 4x, 3x 120% cp = 40.32 100% cp = 33.6 5kg = 33.6*5 = 168 168/7 = 24 24*4/3 = 32 24*3/2 = 36 Or 8x 9x 33.6 3 2 (33.6-8x)/(9x-33.6) = 2/3 3*33.6 - 24x = 18x - 2*33.6 42x = 168 x=4 8x=32, 9x=36 Or (24x+18x)/5----- cost of per kg 42x/5 40.32 sp...so cp= 40.32*10/12= 33.6 atq 42x/5= 33.6 x=4 price per kg 8*4=32. 9*4=36

Two type of rice are mixed in ratio 3:2. If the price of rice is in the ratio 8:9 and mixture is sold at 20% profit then find the price of each type of rice. Given that mixture was sold Rs 40.32 per kg.

M (A) = 120/100 M (B) M (A) : M (B) = 6 : 5 A --- M : W = 9 : 2 B --- M : W = 5 : 2 M (A) : M (B) = 6 : 5 × 45 M (A) : M (B) = 270 : 225 9 - 270 ,,,,, 2 - 60 5 - 225 ,,,,, 2 - 90 A --- M : W = 270 : 60 B --- M : W = 225 : 90 M (C) = 270 + 225/2 = 495/2 = 247.5 M (C) = 247.5 270 + 60 = 330 225 + 90 = 315 15 --- 4 1 --- 4/15 247.5 × 4/15 : 90 × 4/15 2475 : 900 495 : 180 99 : 36 11 : 4

SBI Clerk Mains 2021 Question #Mains #Sbiclerk join 👉 @QuantShine comment your answer

R>Q(average of first n numbers will be less than average of next m numbers) {Q} {R} P. R-P. Q-P (R-P)/(-Q+P)== n/m=3/2 Rest is yours Without allegation (nQ+mq)/(m+n)=P m/n=2k/3k (3qk+2pk)=5pk Hence the answer

W:M 15:27=42 5:9)*17= 85:153 11:17)*9=99:153 Sp=16*(99+153)+18×42=4788 Cp= 153+27)*24=4320 Profit=468₹ Or direct ta find panuradhu than easier ilana mean overall price alligation potu find pannanum 42/14*9-->27 litres 18/28         0           17/28 17.              1 17*14--- 238 *9/14---153 milk 18       16        X 1.          6 X == 16(2/7)₹ 114*16(2/7) - 180*7(5/7) == 468₹ Or (238+14)*16 + 42*18 - 180*24 == >468 Or 11: 17 5: 9 ------------ 14: 0 Cross multiply 14---9*14 28----252 252-14=238 Initial=238+42=280 M--180, w--100 Cp=180*24=4320 Sp=42*18+252*16=4788 P=468

A a   100-a == c B b   100-b == d case 1 : a*a   b*d      a*c      d*d ------+ -----  = ------  + -------  a+c   b+d     a+c      b+d case 2: b*b    c*a      d*b      c*c ------ +------  =  ------- + ------ b+d   a+c      b+d     a+c (1)+(2)   a²      c²        b²       d² ------ - ------ + ------- - ------- = 0 a+c   a+c    b+d     b+d (a-c)(a+c)     (b+d)(b-d) ---------------  +  ---------------  = 0    a+c                 b+d a-100+a+b-100+b=0 a+b==100

X=16 , y = 4. Hit trail x has 6 l water, that means it also has 10 l milk (ratio is 5:3) Similarly, after 16 l taken out milk remaining is 30l 15:11 means water is 22l... Hence y is 4l ie 22-18, Or 5. 3 5x/8. 3x/8 3x/8=6 X=16 40. 24 10. 6 30. 18 +y 30. 22 Y=4 X=16 X/y^3=16/64=1/4 Now option 2nd option satifies..

2*2:::::5*2==7*2 3*3:::::4*3==7*3 19:::22==41*9*k 4::::::5==9*41 (171k+164)/(198k+205)=33/47 Now proceed u will get the desired result

Let's focus on spirit content only. As we are mixing 2/7 (spirit/whole) with 3/7 (spirit/whole) in the ratio 2 : 3, the resulting mixture will have 13/35 (spirit/whole). Now this 13/35 mixture is to be mixed with 4/9 mixture to get 33/80, so the required ratio will be 4/9 - 33/80 : 33/80 - 13/35 => 35(320-297) : 9(1155 - 1040) => 35•23 : 9•115 => 7 : 9

Basic. X. Y Petrol. P. Liquid N. P+120 S=6q.{N} +. P*q/100{P} Tank y=(p+120-6q)/9{N} Mix T {N}5(p+120-6q)/9 ,,,,,,,{P}3*(1-q/100)*p/8==308 Mix U {N}(4/9)*(p+120-6q),,,,{P}5*(1-q/100)*p/8 2p(1-q/100)/8==72 p(1-q/100)==288 p+120-6q=360 p-6q=240 288*100/(100-q)=6(q+40) 4800=(100-q)(q+40) 4800=100q-q^2+4000-40q q^2-60q+800=0 (q-40)(q-20)=0 q=40,20 For ,p>400 q must be 40 Hence N=p+120=240+6*40+120=600

5------0     4 4-------1,4=1,5=1.25 32-----44      X 1-------1 2x=76,x=38% Or 6:14   a 3:17 8:17  b so a=11:14 final 19:31 38 %